Can someone explain to me the principle of calculating PI in this way and the three for statements


#include"stdio.h"
#include"stdlib.h"

long a =10000, b = 0, c = 10000,d,e,f[10001],g;

int main(int argc, char const *argv[])
{
    for(; b != c; f[b++] = a/5);
    for(; d = 0,g = c*2,c>5000;c--,printf("%.4d",e+d/a),e = d%a)
    for(b = c;d += f[b]*a,f[b]=d % --g, d /= g--, --b; d*=b );

    system("pause");//这行和上面的第二个include是我自己加的。
    return 0;
}

I find my understanding of the for statement and the c language is still very poor. This is a code for PI. I don't understand how it works. Can someone explain to me the principle of calculating PI in this way and the three for statements?
Thank you for your trouble.

Can someone explain to me the principle of calculating PI in this way and the three for statements

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D2543691 注册会员
2023-01-25 20:02

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This code is used to calculate PI. PI is an irrational number that can be approximated by an algorithm. This is a method called Mobius series.

The first for statement is to initialize the array f such that f[b] = a/5(where b is the loop variable and a is 10000).

The second for statement is the main loop, with c decreasing from 10000 to 5000. In each loop, by calculating the values of d and e, output the value of e+d/a and assign the value of e to d mod a.

The third for statement evaluates the values of d, f[b], and g in the second for statement. B from c, d + = f [b] a, [b] = d mod - g, f/d = g -, - b, d = b.

The output of this program is the approximate value of PI.

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Publish Time: 2023-01-25 20:02

Update Time: 2023-01-25 20:02