0
Follow
2
View

When an element is inserted from a ring queue

dongkai0919 注册会员
2023-02-25 12:23

This answer refers in part to GPT, GPT_Pro to better solve the problem.
When inserting an element from a ring queue, the usual procedure is to determine whether the queue is full. New elements can be inserted at the end of the queue. Specifically, let the tail pointer point to the new element, and then store the contents of the new element in the position that the tail pointer points to; Finally, the tail-pointer is incremented by one. If the tail-pointer exceeds the maximum space of the ring queue, the tail-pointer can be moved back to position 0(that is, to store the new element from scratch).

For example, we have a ring queue of type int, which has two variables, front and rear, representing the position of the head and tail of the queue respectively; The ring queue can store up to maxSize ints. When we want to insert an int into the ring queue, we use the following code:

// 先判断是否已满
if((rear+1)%maxSize != front)
{
    // 将data插入到队尾的位置
    queue[rear] = data; 
    // 将rear加1,并将rear返回至0,从头开始存储新元素 
    rear = (rear+1) % maxSize; 
} 

If the answer is helpful, please accept it.

d12208 注册会员
2023-02-25 12:23

This answer quotes ChatGPT

When

inserts an element into a ring queue, the usual operations include the following steps:

1. First, check whether the queue is full. If the queue is full, no new elements can be inserted.

2. If the queue is not full, insert the new element into the end of the queue and move the end pointer back one bit. This can be done using subscripts such as rear =(rear + 1) % queue_size.

3. If the queue is empty, you also need to point the queue header pointer to the new element to ensure that the queue is correct.

Notice that when an element in a ring queue is queued, the pointer is moved before the element is stored. That is, move the tail pointer back one bit before placing the element in that position. This is because the end-queue pointer in a ring queue is looped, so the pointer needs to be moved first to ensure that the insertion operation is correct.

About the Author

Question Info

Publish Time
2023-02-25 12:23
Update Time
2023-02-25 12:23