Dynamically allocates a block of struct-sized memory data for the struct pointer; Once allocated, the structure pointer can be used as a structure variable using
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Dynamically allocates a block of struct-sized memory data for the struct pointer; Once allocated, the structure pointer can be used as a structure variable using
This answer refers in part to GPT, GPT_Pro to better solve the problem
After line 9, headnode becomes a struct variable because line 9 is initializing a linked list, It allocates memory for the head node and uses it as the head of the linked list.
struct node * headnode = (struct node*)malloc(sizeof(struct node));
line creates the header by applying for a block of memory, converting it to a struct node*, and assigning it to the headnode. This results in a header node, which becomes a structure variable. This header node is the beginning of the linked list, and each node added in turn is linked after the node pointed to by the headnode, forming a linked list.
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the reference answer GPT ᴼ ᴾ ᴱ ᴺ ᴬ ᴵ < br / > the headNode line 9 is a pointer variable, which points to a dynamically allocated memory space, The space size is the size of a structure Node, which is allocated a node containing a data field and a pointer field. Since malloc() returns a pointer to allocated memory, it needs to be cast to the struct Node* type before it can be assigned to headNode.
When creating a linked list, line 9 is used to create the head node, which serves as the starting position of the linked list and facilitates subsequent node addition and access. The data field for this header node can be empty because it does not store any actual data, and the pointer field needs to point to the first actual node of the linked list.
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