Problem with #idea# : The above error occurred while connecting to the database(language-Java)

cwl6985839cwl 注册会员
2023-02-25 18:04

the reference answer GPT ᴼ ᴾ ᴱ ᴺ ᴬ ᴵ < br / > this error is usually brought about because of the file name or path is too long. In Windows, the maximum length of a file pathname is 260 characters, including the file name, directory name, and separator. If this limit is exceeded, this error occurs.

There are some solutions to try:

  1. shortens the file path or file name to a shorter name.
  2. puts the folder in the root directory so that the path is shorter.
  3. use the UNC path(e.g., \server\share\file) instead of the drive letter path(e.g., C:\path\file).
  4. Try to use relative paths instead of absolute paths.
  5. Moves the project folder to a shorter path.

If none of the above fixes the problem, you may want to consider rearranging the project file structure or using abbreviations instead of excessively long file names.

dongliming128 注册会员
2023-02-25 18:04
  • One is that there are too many jars in the classpath, so the java command cannot be executed in the window. CreateProcess error=206 is reported. The file name or extension is too long.
  • The name of your java file or package is too long, causing the window to execute the java command. CreateProcess error=206 is reported, and the file name or extension is too long.
  • Look at the console of idea and take a screenshot to see the printed java command; After running, something like


dille1028 注册会员
2023-02-25 18:04

The answer part references GPT, GPT_Pro better solve the problem
This error is caused by the filename or extension being too long, that is, when connecting to the database, A file name or extension is too long. Generally, Windows does not allow the total length of file names and extensions to exceed 260 characters. Therefore, this problem occurs when the file path is too long.

The most direct way to solve this problem is to reduce the length of the file path, or rename the file name and extension so that it meets Windows requirements.

If you are programming in the Java language, you can use the following code to solve the problem:

String pathName = "C:\\Program Files\\MyDatabase\\mydatabase.db";
// 尝试重命名文件名和扩展名
String[] pathParts = pathName.split("\\");
String newPathName = "";
for(int i = 0;i < pathParts.length;i++) {
    if(i < pathParts.length - 1) {
        // 将前面不超过 8 个字符的文件名或文件夹名改为 8 个字符
        if(pathParts[i].length() > 8) {
            pathParts[i] = pathParts[i].substring(0,8);
        newPathName += pathParts[i] + "\\";
    } else {
        // 检查文件扩展名是否超过 3 个字符,如果是则将其截断到 3 个字符
        String[] fileNameParts = pathParts[i].split("\\.");
        String newFileName = fileNameParts[0];
        if(fileNameParts[1].length() > 3) {
            newFileName += "." + fileNameParts[1].substring(0,3);
        } else {
            newFileName += "." + fileNameParts[1];
        // 连接重命名后的文件路径字符串
        newPathName += newFileName;
// 输出重命名后的文件路径字符串
System.out.println(newPathName);  // C:\Program\MyDatab\mydatab.db 

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Publish Time
2023-02-25 18:04
Update Time
2023-02-25 18:04

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