Pointer variable print string problem

Use the %s format specifier of the printf() function.

int main() {
    char* str = "www.dotcpp.com";
    printf("str=%s\n", str); // 使用%s打印字符串
    return 0;
}

This program prints www.dotcpp.com. In the format string of the printf() function, %s indicates that a string is to be printed, and the corresponding argument is a pointer to the string. Therefore, we can take the pointer to the string directly as an argument to the printf() function and print out the entire string using the %s format specifier.

printf("str=%x,*str=%c", str, str); str=%c is just the first element of the output string. The correct output is printf("str=%s\n", str);

This answer partially references GPT and GPT_Pro to solve the problem better.
You can print a string using a pointer variable. The principle is to put the string in memory and then point the pointer to the memory address. Finally, by traversing the memory address to which the pointer points, we can output the string information to which the pointer points.

1. First define a character array in memory to store the string information to be output.

   char str[10] = "Hello";  // 定义一个字符数组，用来存储要输出的字符串
   

2. then defines a pointer variable and points that variable to the character array defined above.

   char *p = str;  // 定义一个指针变量，并把该变量指向上述定义的字符数组
   

3. Finally traverses the memory address to which the pointer variable points, and prints the string information to which the pointer points.

   while(*p != '\0')  // 遍历该指针变量指向的内存地址，直到遇到'\0'为止
   { 
    printf("%c", *p);  // 输出当前内存地址中的字符 
    p++;  // 指针变量 + 1
   } 
   

   That's how you print a string from a pointer variable, but the key is to use pointer variables to iterate over what you want to print. Of course, we can also use other methods, such as for loops, while loops, etc.
   If the answer is helpful, please accept it.