Then calculate and output the number of all positive, negative, and zeros in the array

#include 
int main()
{
    int i, m = 0, n = 0,b=0;
    int a[10];
    printf("请输入10个整数：\n");
    for (i=0; i<10; i++)
    {
        scanf("%d", &a[i]);
        if (a[i] > 0)
        {
            m++;
        }
        if (a[i] < 0)
        {
            n++;
        }
        if (a[i] == 0)
        {
            b++;
        }
    }
    printf("正数个数：%d\n", m);
    printf("零的个数：%d\n", b);
    printf("负数个数：%d", n);
}

This answer quotes ChatGPT

Here is a program written in C# to input 10 integers, store them in an array, and then calculate and output the number of all positive, negative, and zeros in the array.

using System;

class Program
{
    static void Main(string[] args)
    {
        int[] numbers = new int[10];
        int positiveCount = 0, negativeCount = 0, zeroCount = 0;

        Console.WriteLine("请输入10个整数：");

        // 读取输入的10个整数并存储在数组中
        for (int i = 0; i < 10; i++)
        {
            Console.Write("第{0}个数：", i + 1);
            numbers[i] = Convert.ToInt32(Console.ReadLine());
        }

        // 计算数组中的正数、负数和零的个数
        foreach (int number in numbers)
        {
            if (number > 0)
            {
                positiveCount++;
            }
            else if (number < 0)
            {
                negativeCount++;
            }
            else
            {
                zeroCount++;
            }
        }

        // 输出结果
        Console.WriteLine("数组中有{0}个正数，{1}个负数，{2}个零。", positiveCount, negativeCount, zeroCount);
    }
}

In this program, we first declare an array of 10 integers, numbers, and the variables positiveCount, negativeCount, and zeroCount, which store the number of positive, negative, and zeros, respectively.

Then, we use a for loop to read 10 integers and store them in the array numbers. Next, you use a foreach loop to iterate through each element in the group, incrementing the counters for positive, negative, and zero based on the element's value. Finally, we output the counter value to get the number of all positive, negative, and zeros in the array.