The answer is D, many people don't understand...

If char str[10]="hello ", the following statement is incorrect.
Aprintf("%s",str);
Bprintf("%c",str[0]);
Cscanf("%s",str);
Dscanf("%c",str[0]):

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dxboy999 注册会员
2023-02-28 04:26

the reference answer GPT ᴼ ᴾ ᴱ ᴺ ᴬ ᴵ < br / > D.

Because scanf("%c", str[0]) should have a character type as its argument type, not a character array type, scanf("%c", & str[0]).

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cyok5656 注册会员
2023-02-28 04:26

D, the character input should add the address &

scanf("%c", &str[0]);

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